(1/7)^a+3=1

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Solution for (1/7)^a+3=1 equation: 



(1/7)^a+3=1

We move all terms to the left:

(1/7)^a+3-(1)=0



Domain of the equation: 7)^a!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

(+1/7)^a+3-1=0

We add all the numbers together, and all the variables

(+1/7)^a+2=0

We multiply all the terms by the denominator


(+1+2*7)^a=0

We add all the numbers together, and all the variables

15^a=0

a=0/1

a=0

Równanie nie ma rozwiązania

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